A simple logic problem

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Woah, woah, Daddy's wrong, Mommy's right.
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Make that 26 and 41 for me, with JABrady that is

37 BB
61 BG

or 62.5%
 

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wow. this is crazy. im on my mobile, but if someone could draw up a simple flow chart to demonstrate that the answer is 2/3...

boy
boy

boy
girl

girl
girl

girl
boy

first one is first born, second is the second born.

what the fuck is wrong with you guys not thinking its 2/3 ???!!?!! its 2/3. this thread needs to be locked or some shit. i mean.... really?? i was SURE it was 50percent but realized i was wrong. I FEEL LIKE IM TAKING CRAZY PILLS!!:cripwalk::party::wink::pope::smoking:
 

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I answered the question presuming the guy talking about a son could be talking about either of his two kids. Thought about the averages of the second one's sex....that's where I got the 50%. Haven't read the whole thread but I think back to the chicken that someone made an alleged seven dollars on, was that ever finalized?
 

I can't dance
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Fucking unbelieveable.

I read the 1st page of this thread, and now it is 15 pages long?

The answer is 50%, and there is no arguement.

Here is the proof.

Consider these four statements.

A woman is about to give birth to her first child. What is the probability of it being M/F?

A woman is a mother of one child. What is the probability of it being M/F?

A woman has one child, and is about to give birth to her second child next week. What is the probability of it being M/F?

A woman has two children. She spoke of her eldest being a boy. What is the probability of the second child being M/F?

These fucking four statements say the exact same fucking thing! It's 50%!!

That's why people lose at gambling. Cannot do math. Cannot even read English!

Whew! Glad to get that off my chest, LOL.

:nohead:
 

I can't dance
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it is not 50-50 that is the issue
But that is a bleeping non issue.

If both outcomes are dependent or related to each other, then it is a factor.

But dice or birth has no memory.

The children may be related by family ties, not mathematical probability ties.
 

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Fucking unbelieveable.

I read the 1st page of this thread, and now it is 15 pages long?

The answer is 50%, and there is no arguement.

Here is the proof.

Consider these four statements.

A woman is about to give birth to her first child. What is the probability of it being M/F?

A woman is a mother of one child. What is the probability of it being M/F?

A woman has one child, and is about to give birth to her second child next week. What is the probability of it being M/F?

A woman has two children. She spoke of her eldest being a boy. What is the probability of the second child being M/F?

These fucking four statements say the exact same fucking thing! It's 50%!!

That's why people lose at gambling. Cannot do math. Cannot even read English!

Whew! Glad to get that off my chest, LOL.

:nohead:


:ohno::ohno::ohno::ohno::ohno::ohno::ohno::ohno::ohno::ohno::ohno::ohno::ohno::ohno::ohno::ohno:

I am done with this thread:toast:
 

Woah, woah, Daddy's wrong, Mommy's right.
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But that is a bleeping non issue.

If both outcomes are dependent or related to each other, then it is a factor.

But dice or birth has no memory.

The children may be related by family ties, not mathematical probability ties.

Since you didn't read the entire thread, excluding the possibility of two girls, what is the probability that a family with two children has one boy and one girl?
 

Oh boy!
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I see we have a new group of people for the night who may not have read or discussion from the day so I'll repeat myself.

The wording is tricky. Most people are confusing "other child" to mean "remaining child".

When the question asks "other child" it opens up the case where the child can be oldest or youngest since these possibilities exist. Therefore "other child" can mean older or younger as well and that gives us 3 total possibilities of which 2 can be a girl.
 

HAT

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Screw the math...As the title states, this is a LOGIC problem, not a math, statistics or probability problem.

A man tells you he has two children. He then starts talking about his son. He does not tell you whether the son is the oldest child or the youngest child. What is the probability that his other child is a girl?

If he "He does not tell you whether the son is the oldest child or the youngest child"....than it's safe to assume that it NEVER came up. Therefore the problem would read.....

A man tells you he has two children. He then starts talking about his son. What is the probability that his other child is a girl?

LOGICALLY the answer is 50%.

IF the question read:

A man tells you he has two children. He then starts talking about his son. He then tells you that the son may be the older child or he may be the younger child. What is the probability that his other child is a girl?

Then the math kicks in and the answer is 66.7%

Left brain vs. right brain.
 
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Screw the math...As the title states, this is a LOGIC problem, not a math, statistics or probability problem.



If he "He does not tell you whether the son is the oldest child or the youngest child"....than it's safe to assume that it NEVER came up. Therefore the problem would read.....



LOGICALLY the answer is 50%.

IF the question read:



Then the math kicks in and the answer is 66.7%

Left brain vs. right brain.


Bzzzt. Logically the answer is not 50%.

Try again.
 

HAT

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did you even read my post? Any logical person would remove this sentence from the equation

"He does not tell you whether the son is the oldest child or the youngest child".

Because, LOGICALLY, you can infer that it never came up.

He's either got a BG or a BB.

If he did mention that the the Boy may be the eldest or he may be the youngest....Than of course the math dictates 67%
 

Oh boy!
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Originally Posted by MrMore
I flip 2 coins in the air and catch one in each hand, then slam them down on the table.

I turn over my left hand and reveal heads.

What are the chances the coin under the my right hand is tails?



this example, no doubt 50%

the part that is confusing is that if you peek at both and tell us ONE of them is heads (not revealing which hand), you are left with 3 possible scenarios:

right hand: heads ; left hand: heads
right hand: heads ; left hand: tails
right hand: tails ; left hand: heads

they are saying that in 2/3 of the scenarios, the "other" coin is tails.....

....the logic is easy to comprehend....much harder to believe.

Here is shdw01's explanation that takes out the older child/younger child scenario. I feel this puts all questions to rest.
 

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I see we have a new group of people for the night who may not have read or discussion from the day so I'll repeat myself.

The wording is tricky. Most people are confusing "other child" to mean "remaining child".

When the question asks "other child" it opens up the case where the child can be oldest or youngest since these possibilities exist. Therefore "other child" can mean older or younger as well and that gives us 3 total possibilities of which 2 can be a girl.

Have fun with the new group QL :lolBIG:

:toast:
 

Oh boy!
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did you even read my post? Any logical person would remove this sentence from the equation

"He does not tell you whether the son is the oldest child or the youngest child".

Because, LOGICALLY, you can infer that it never came up.

He's either got a BG or a BB.

If he did mention that the the Boy may be the eldest or he may be the youngest....Than of course the math dictates 67%

Take out the fact that one is older than the other. Say that he has twins, one boy and one girl. If he says one child is a boy, what are the chances that the other is a girl? "The other" does not mean "remaining child" in this situation. That's the confusing point. "The other" means how many possibilities is the child not a boy.

2 out of 3:
1 child is a girl, the other child is a boy
1 child is a boy, the other child is a girl
1 child is a boy, the other child is a boy

You have to have 2 separate possibilities for 1 boy/1 girl since there are 2 separate children.
 

HAT

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Here is shdw01's explanation that takes out the older child/younger child scenario. I feel this puts all questions to rest.

"He does not tell you whether the son is the oldest child or the youngest child"

Therefore, you are not being asked to even considerthe order in which they came. Or in Shadows example...left hand or right hand.

The only question being asked in the original post is:

What is the probability that any given child is a female."He does not tell you whether the son is the oldest child or the youngest child"

If he doesn't tell you, it never came up. Age/order is not a consideration.

If I asked you:

"What's up QL, I've got 2 kids & one is a boy. What are the chances the other is a girl?"

What is your answer?

It's my contention that it is illogical to interpret the following the sentence:"He does not tell you whether the son is the oldest child or the youngest child"

To mean:

"He tells you the son could be the oldest child or could be the youngest child"

(Heads may be in the left hand or may be the right hand)
 

HAT

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Totally agree that the hang up is on "other" and "remaining"

But to me....Logically, if he doesn't tell you, then it never came up and the question therefore is "remaining"

I'm not disputing the math.
 

Oh boy!
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If I asked you:

"What's up QL, I've got 2 kids & one is a boy. What are the chances the other is a girl?"

What is your answer?

I would answer the same way. See my previous post #376 in this thread. One being older than the other doesn't matter.

What DOES matter is that they are 2 separate individuals and therefore "chances" as asked in the question must take "1 boy/1 girl" and "1 girl/1 boy" as 2 separate "chances". The third "chance" is that he has 2 boys.
 

gerhart got hosed
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I would answer the same way. See my previous post #376 in this thread. One being older than the other doesn't matter.

What DOES matter is that they are 2 separate individuals and therefore "chances" as asked in the question must take "1 boy/1 girl" and "1 girl/1 boy" as 2 separate "chances". The third "chance" is that he has 2 boys.

I undestand what you are saying but if there is 2 separate chances for 1 boy one girl, why is there not 2 separate chances for 2boys (ba/bb, bb/ba)?

I say the chances are either:

BB
BG (GB is the same thing)

or

BaBb
BG
GB
BbBa
 

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