Fucking unbelieveable.
I read the 1st page of this thread, and now it is 15 pages long?
The answer is 50%, and there is no arguement.
Here is the proof.
Consider these four statements.
A woman is about to give birth to her first child. What is the probability of it being M/F?
A woman is a mother of one child. What is the probability of it being M/F?
A woman has one child, and is about to give birth to her second child next week. What is the probability of it being M/F?
A woman has two children. She spoke of her eldest being a boy. What is the probability of the second child being M/F?
These fucking four statements say the exact same fucking thing! It's 50%!!
That's why people lose at gambling. Cannot do math. Cannot even read English!
Whew! Glad to get that off my chest, LOL.
:nohead:
But that is a bleeping non issue.
If both outcomes are dependent or related to each other, then it is a factor.
But dice or birth has no memory.
The children may be related by family ties, not mathematical probability ties.
A man tells you he has two children. He then starts talking about his son. He does not tell you whether the son is the oldest child or the youngest child. What is the probability that his other child is a girl?
A man tells you he has two children. He then starts talking about his son. What is the probability that his other child is a girl?
A man tells you he has two children. He then starts talking about his son. He then tells you that the son may be the older child or he may be the younger child. What is the probability that his other child is a girl?
Screw the math...As the title states, this is a LOGIC problem, not a math, statistics or probability problem.
If he "He does not tell you whether the son is the oldest child or the youngest child"....than it's safe to assume that it NEVER came up. Therefore the problem would read.....
LOGICALLY the answer is 50%.
IF the question read:
Then the math kicks in and the answer is 66.7%
Left brain vs. right brain.
this example, no doubt 50%
the part that is confusing is that if you peek at both and tell us ONE of them is heads (not revealing which hand), you are left with 3 possible scenarios:
right hand: heads ; left hand: heads
right hand: heads ; left hand: tails
right hand: tails ; left hand: heads
they are saying that in 2/3 of the scenarios, the "other" coin is tails.....
....the logic is easy to comprehend....much harder to believe.
I see we have a new group of people for the night who may not have read or discussion from the day so I'll repeat myself.
The wording is tricky. Most people are confusing "other child" to mean "remaining child".
When the question asks "other child" it opens up the case where the child can be oldest or youngest since these possibilities exist. Therefore "other child" can mean older or younger as well and that gives us 3 total possibilities of which 2 can be a girl.
did you even read my post? Any logical person would remove this sentence from the equation
"He does not tell you whether the son is the oldest child or the youngest child".
Because, LOGICALLY, you can infer that it never came up.
He's either got a BG or a BB.
If he did mention that the the Boy may be the eldest or he may be the youngest....Than of course the math dictates 67%
Here is shdw01's explanation that takes out the older child/younger child scenario. I feel this puts all questions to rest.
If I asked you:
"What's up QL, I've got 2 kids & one is a boy. What are the chances the other is a girl?"
What is your answer?
I would answer the same way. See my previous post #376 in this thread. One being older than the other doesn't matter.
What DOES matter is that they are 2 separate individuals and therefore "chances" as asked in the question must take "1 boy/1 girl" and "1 girl/1 boy" as 2 separate "chances". The third "chance" is that he has 2 boys.