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morally bankrupt
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Even though I got it wrong also, I busted out laughing when levi talked shit about how easy the question was, gave the wrong answer, then showed how he got the wrong answer, which made no sense at all.

What are you talking about?

He has the right answer, and this IS an easy SAT question.

You have to omit the unnecessary information from the problem, which is the 1,000 bulbs. That information is not relevant to the question. It could be 343,202,766 bulbs and the answer is still the same.

If 1 out of every 40 bulbs are defective than the ratio between defective and non-defective bulbs is 1 defective for 39 non-defective.

It really isn't complicated.
 

" Thanks for tip Bricktop "
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1/40

Take the 1000 sampling

25/975 broken down the lowest denominator is 1/39

1.39
 

Rx God
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it says 1/40 of the bulbs are defective, not 40.

You are right. I read it as 40 defective,just noticed it was the fraction 1 over 40. My bad.

How do you even type in a fraction like that ?

Therefore 1:39 is correct

Apoligies to Levi
 

morally bankrupt
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How do you even type in a fraction like that ?

Any whole # can be written as a fraction if you just put 1 as the denominator. So 40/1 if you're talking 40.

Edit: Maybe you just meant the way he posted it so it looked like a fraction, no idea.
 

Rx God
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Any whole # can be written as a fraction if you just put 1 as the denominator. So 40/1 if you're talking 40.

Edit: Maybe you just meant the way he posted it so it looked like a fraction, no idea.


Yeah,that's what got me, the way it was posted as a fraction, I don't know how to do that, I read it as 40 bad ( small type).
 

New member
Joined
Sep 11, 2005
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Even though I got it wrong also, I busted out laughing when levi talked shit about how easy the question was, gave the wrong answer, then showed how he got the wrong answer, which made no sense at all.

What are you talking about?

He has the right answer, and this IS an easy SAT question.

You have to omit the unnecessary information from the problem, which is the 1,000 bulbs. That information is not relevant to the question. It could be 343,202,766 bulbs and the answer is still the same.

If 1 out of every 40 bulbs are defective than the ratio between defective and non-defective bulbs is 1 defective for 39 non-defective.

It really isn't complicated.

hahaai9.jpg


I got a 1330 on the SAT, I think I can do simple stuff like this. I can post some harder stuff that no only a few will get right.
 

USERNAME OFFICIALLY RETIRED
Joined
Nov 29, 2004
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a12g1.gif
of 1,000 light bulbs were defective, so
a12g1.gif
(1,000) or 25 bulbs were defective. The rest, 1,000 – 25 or 975, were nondefective. The ratio of defective to nondefective is
a12g2.gif
=
a12g3.gif
.



fucnluc shoots straight up to the front of the class. He answered it first and in no time.
 

EV Whore
Joined
Apr 18, 2006
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I got a 1330 on the SAT, I think I can do simple stuff like this. I can post some harder stuff that no only a few will get right.

Woo hoo, good for you. Apparently you missed the 270 points in the English section...

I can post some harder stuff that no only a few will get right.
 

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