With the regular blackjack rules a dealer's hand will bust 28.36% of the time. This is according to a website I found, but could NOT find the answer to my question, which is this: What are the odds of a dealer not busting for 12 (that's Twelve) straight hands. Now for this to happen at least one player at the table would have to stand with something less than 21 of course; in order for the dealer to be required to take extra cards. I can't find an answer, but know there are some very smart people here.. Thanks
Another way to figure it out is from an odds point of view rather than a percentage point of view (a small percentage with a bunch of zero doesnt compute for most people)
An outcome with a 28.36 chance of happening on one trial means it will
happen 1 in 3.52 times
so to calculate it happening 12 times in a row we can take 3.52 to the 12th power and we get 3618361
An outcome with a 28.36 chance of happening on one trial means it will
happen 1 in 3.52 times
so to calculate it happening 12 times in a row we can take 3.52 to the 12th power and we get 3618361
Okay. I was at a casino recently and not a fan of table games with the crowds of being elbow to elbow these days. Broke about even on the sports bets for a few days. Anyway, I took notice of the table minimum and maximum bets. At Blackjack, Roulette and Craps; each had a table minimum bet of $15 while I was there. The HUGE difference is that only the Blackjack tables had a MAXIMUM bet of $500, which is quite low compared to Craps Max and Roulette maximum on the outside bets of odd-even; red-black type. I watched blackjack for a while and saw a dealer go 12 hands without busting and thought this was extremely given the low Maximum for blackjack.
